02-02-2026 21:46
Margot en Geert VullingsOn a barkless poplar branch, we found hairy discs
02-02-2026 14:55
Andgelo Mombert
Bonjour,Sur thalle de Lobaria pulmonaria.Conidiome
02-02-2026 14:33
Andgelo Mombert
Bonjour,Sur le thalle de Peltigera praetextata, ne
31-01-2026 10:22
Michel Hairaud
Bonjour, Cette hypocreale parasite en nombre les
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Bernard CLESSE
Bonjour à toutes et tous,Pour cette récolte de 2
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Nicolas Suberbielle
Bonjour, Marie-Rose D'Angelo (Société Mycologiq
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Marc Detollenaere
Dear Forum,On decorticated wood of Castanea,I foun
29-08-2025 05:16
Francois Guay
I think I may have found the teleomorph of Dendros
30-01-2026 21:20
Arnold BüschlenBryocentria brongniartii und B. metzgeriae mit ihr
Rhodotarzetta's anamorph ?
Nina Filippova,
01-03-2015 13:22
I have something Botrytis- like that may by an anamorph of Rhodotarzetta rosea in culture but i am not sure. I have inoculated dried pieces of apothecia and there were similar looking colonia in all Petri dishes. I am only learning in cultivation technique (it is still winter, therefore i use dried material) and thefore could have mistakes. Please, if you have some suggestion about this anamorphic species, it would be wonderful to know.
Potato-glucose-yeast-agar-charcoal (PH7): Colonia fast growing (9 cm in 3 days), grayish, with brownish conidial mass, pubescent, floccose and forming small sclerotia-like blobs, with not distinct radial zonation.
Yeast-agar-charcoal (PH7): Similar characteristics, but colonia much thinner, slowly growing and conidia barely forming.
Conidiophores about 5 broad, dichotomously branched, terminal fertile cells inflated up to 12 in diameter, producing conidia on short stalks; conidia ellipsoid, with short stalk, pale colored, light brownish in mass by naked eye, *13.7 (9,8-16.2) [17.7] x 6.7 (6-7.7), n=15.
The inoculation of a swan (sand-bran-charcoal) produced extensive growth, all volume was colonized in a week; no apothecia formed so far.
Hans-Otto Baral,
01-03-2015 15:24
Re : Rhodotarzetta's anamorph ?
Did you compare Oedocephalum? I am not familiar here but this would be my first idea.
Zotto
Zotto




